Forever Calender in C++ - Beginners / Lab Assignments Source Code in C++

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Home » C++ Home » Beginners / Lab Assignments Home » Forever Calender in C++

A D V E R T I S E M E N T

Title	Forever Calender in C++
Author	R.Bharath
Author Email	r_bharath25 [at] yahoo.co.in
Description	You can see the calender of any month of any year with this program.
Category	C++ » Beginners / Lab Assignments
Hits	392640
Code	Select and Copy the Code
#include<iostream.h> #include<conio.h> int step1 (int); void month_name(int); int no_days(int,int); int leap(int); void main() { restart: clrscr(); cout<<"Enter year : "; unsigned int y,m; cin>>y; int x; x=step1(y); int month[14][12]= {1,4,4,7,2,5,7,3,6,1,4,6, 2,5,5,1,3,6,1,4,7,2,5,7, 3,6,6,2,4,7,2,5,1,3,6,1, 4,7,7,3,5,1,3,6,2,4,7,2, 5,1,1,4,6,2,4,7,3,5,1,3, 6,2,2,5,7,3,5,1,4,6,2,4, 7,3,3,6,1,4,6,2,5,7,3,5, 1,4,5,1,3,6,1,4,7,2,5,7, 2,5,6,2,4,7,2,5,1,3,6,1, 3,6,7,3,5,1,3,6,2,4,7,2, 4,7,1,4,6,2,4,7,3,5,1,3, 5,1,2,5,7,3,5,1,4,6,2,4, 6,2,3,6,1,4,6,2,5,7,3,5, 7,3,4,7,2,5,7,3,6,1,4,6}; cout<<"Enter month (1 - 12) : "; month_input: cin>>m; if(m<1 \|\| m>12) { cout<<"Enter a valid month (1 - 12) : "; goto month_input; } cout<<" "; month_name(m); cout<<' '<<y<<" Mon Tue Wed Thu Fri Sat Sun "; int j=month[x-1][m-1], days=no_days(m,y); for (int i=0; i<j-1; i++) cout<<' '; for(i=1; i<=days; i++) { cout<<i<<' '; if(j==7) { cout<<' '; j=1; } else j++; } cout<<" Try for another month? (y/n) : "; char ch; cin>>ch; if(ch=='y' \|\| ch=='Y') goto restart; } int step1 (int y) { int x=y%7; x+=(y-1)/4; x-=(y-1)/100; x+=(y-1)/400; x=x%7; if(x==0) x=7; if(leap(y)) x+=7; return x; } void month_name(int m) { switch(m) { case 1 : cout<<"January"; break; case 2 : cout<<"February"; break; case 3 : cout<<"March"; break; case 4 : cout<<"April"; break; case 5 : cout<<"May"; break; case 6 : cout<<"June"; break; case 7 : cout<<"July"; break; case 8 : cout<<"August"; break; case 9 : cout<<"September"; break; case 10: cout<<"October"; break; case 11: cout<<"November"; break; case 12: cout<<"December"; break; } } int no_days(int mon, int y) { int d; switch(mon) { case 1 : case 3 : case 5 : case 7 : case 8 : case 10: case 12: d=31; break; case 4 : case 6 : case 9 : case 11: d=30; break; case 2 : if(leap(y)) d=29; else d=28; break; } return d; } int leap (int y) { if (y%100==0) if (y%400==0) return 1; else return 0; else if (y%4==0) return 1; else return 0; }

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