Addition of two very long positive integers(without using linked list -saving memory which is consumed in case of linked list to store address of next node) - Beginners / Lab Assignments Source Code in C++

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Home » C++ Home » Beginners / Lab Assignments Home » Addition of two very long positive integers(without using linked list -saving memory which is consumed in case of linked list to store address of next node)

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Title	Addition of two very long positive integers(without using linked list -saving memory which is consumed in case of linked list to store address of next node)
Author	Sandeep Sindhwani
Author Email	sandeepsindhwani17 [at] rediffmail.com
Description	This code adds two very long integers. Here making this the linked list has been avoided because linked list takes extra memory in storing the address of next node. This code has been implemented using a pointer to a character. The pointer to a character is allocated memory using malloc() function here. But as the length of number is increased then the number is allocated more memory using realloc() function.
Category	C++ » Beginners / Lab Assignments
Hits	382092
Code	Select and Copy the Code
#include<iostream.h> #include<conio.h> #include<string.h> #include<stdlib.h> class long_add { char s1; / First number/ char s2; /* Second number/ char result; /* Final Result/ public: void getnum(); /Function to enter 2 numbers / char long_add::enternum(); /Function to put numbers to strings/ void long_add::addnum(); /Function to add two numbers / void display(); /Function to display result of Addition/ }; void long_add::display() /Function to display result of Addition/ { cout<<" Sum:"; if (result=='0') result++; cout<<result; } void long_add::getnum() /Function to enter 2 numbers / { cout<<" Enter First number:"; s1=enternum(); cout<<" Enter Second number:"; s2=enternum(); } char long_add::enternum() /Function to put numbers to strings/ { char p,s,t; int i=0; while(p!=' ') { p=getche(); if (i==0) { s=(char )malloc(sizeof(char)+1); s=p; } else { s=(char )realloc(s,((i+1)sizeof(char))+1); t=s+i; t=p; } i++; } (s+i)='

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