To perform operations on complex number using operator - Beginners / Lab Assignments Source Code in C++

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Home » C++ Home » Beginners / Lab Assignments Home » To perform operations on complex number using operator

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Title	To perform operations on complex number using operator
Author	saharsh jadhav
Author Email	get_sai2002 [at] yahoo.co.in
Description	In this programe i use the main feature of c++ i.e. operator overloading. By using operator overloading we can overload i.e. use one operator for more than one purpose.
Category	C++ » Beginners / Lab Assignments
Hits	381179
Code	Select and Copy the Code
:#include<iostream.h> #include<math.h> #include<process.h> #include<conio.h> class comp { private: float real,image; public: comp operator +(comp a); comp operator -(comp a); comp operator (comp a); comp operator /(comp a); void getdata(); void show(); }; void comp :: getdata() { cout<<" Enter real part="; cin>>real; cout<<" Enter imaginary part="; cin>>image; } void comp :: show() { cout.precision(2); if(image<0) cout<<real<<image<<"i"; else cout<<real<<"+"<<image<<"i"; } comp comp :: operator +(comp a) { comp temp; temp.real=real+a.real; temp.image=image+a.image; return temp; } comp comp :: operator -(comp a) { comp temp; temp.real=a.real-real; temp.image=a.image-image; return temp; } comp comp :: operator (comp a) { comp temp; temp.real=(a.realreal)-(a.imageimage); temp.image=(a.realimage)+(reala.image); return temp; } comp comp :: operator /(comp a) { comp temp; temp.real=((reala.real)+(a.imageimage))/((realreal)+(imageimage)); temp.image=((reala.image)-(imagea.image))/((realreal)+(imageimage)); return temp; } void main() { comp d,e,f; int ch; char ans; do { clrscr(); cout<<" ******** Menu ******** "; cout<<" 1>Addition"; cout<<" 2>Subtraction"; cout<<" 3>Multiplication"; cout<<" 4>Division"; cout<<" 5>Exit"; d.getdata(); e.getdata(); cout<<" first no=>"; d.show(); cout<<" second no=>"; e.show(); cout<<" enter the choice=>"; cin>>ch; switch(ch) { case 1: f=d-e; cout<<" addition of two no=>"; f.show(); break; case 2: f=d-e; cout<<" subtraction of two no=>"; f.show(); break; case 3: f=d*e; cout<<" multiplication of two no=>"; f.show(); break; case 4: f=d/e; cout<<" division of two no=>"; f.show(); break; case 5: exit(0); break; } cout<<" do you want to continue(y/n)?="; cin>>ans; } while(ans=='y'\|\|ans=='Y'); getch(); }

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