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Title Merging two doubly-linked-lists into another
Author Mokopela Tsepe
Author Email eliatsepemokopela [at] yahoo.com
Description This program will take two doubly-linked lists of nodes and merges them into another doubly-linked list of nodes.
Category C++ » Data Structures
Hits 16195
Code Select and Copy the Code
Code : #include<iostream> using namespace std; class Node { public: int data; Node *next; Node *prev; Node() { data=0; next=prev=NULL; } }; class Node1 { public: int data; Node1 *next; Node1 *prev; Node1() { data=0; next=prev=NULL; } }; class Node2 { public: int data; Node2 *next; Node2 *prev; Node2() { data=0; next=prev=NULL; } }; class DoublyLinkedList { private: Node *headNode, *tailnode; Node1 *headNode1, *tailNode1; Node2 *headNode2, *tailNode2; public: DoublyLinkedList() { headNode=tailNode=NULL; headNode1=tailNode1=NULL; headNode2=tailNode2=NULL; } void Insert();//Insert data into the two lists void Merge() ;//Merging two lists into one void Display();//Display only the merged list }; void DoublyLinkedList::Insert() { char option; //This section inserts elements into the nodes of the first list do { Node *newnode = new Node(); cin>>newnode->data; newnode->next=NULL; newnode->prev=NULL; if(headNode==NULL) { headNode= tailNode=newnode; } else { Node *curr = headNode; while(curr->next!=NULL) { curr=curr->next; } curr->next=tailNode=newnode; newnode->prev=curr; } cout<<"Enter y to continue adding data into the first list :"; cin>>option; } while(option=='y'||option=='Y'); //The section inserts the elements into the nodes of the second list do { Node1 *newnode = new Node1(); cin>>newnode->data; newnode->next=NULL; newnode->prev=NULL; if(headNode1==NULL) { headNode1=tailNode1=newnode; } else { Node1 *curr = headNode1; while(curr->next!=NULL) { curr=curr->next; } curr->next= tailNode1=newnode; newnode->prev=curr; } cout<<"Enter y to continue adding data into the second list :"; cin>>option; } while(option=='y'||option=='Y'); } void DoublyLinkedList::Merge() { Node *currentNode=headNode; Node1 *currentNode1=headNode1; //This section of code copies all the data from list 1 into the new list while(currentNode!=NULL) { Node2 *newnode = new Node2(); newnode->data = currentNode->data; newnode->next = NULL; newnode->prev = NULL; if(headNode2==NULL) { headNode2=tailNode2=newnode; } else { Node2 *temp = headNode2; while(temp->next!=NULL) { temp=temp->next; } temp->next=tailNode2=newnode; newnode->prev=temp; } currentNode=currentNode->next; } //This section of code appends the new list with data from the second list while(currentNode1!=NULL) { Node2 *newnode = new Node2(); newnode->data = currentNode1->data; newnode->next = newnode->prev=NULL; if(tailNode2->next==NULL) { tailNode2->next=newnode; newnode->prev = tailNode2; tailNode2=newnode; } currentNode1= currentNode1->next; } } void DoublyLinkedList::Display() { Node2 *currentNode2 = headNode2; while(currentNode2!=NULL) { cout<<currentNode2->data<<" "; currentNode2=currentNode2->next; } cout<<endl; } void main() { DoublyLinkedList DLL; DLL.Insert(); DLL.Merge(); DLL.Display(); }

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