Number Magic in C. - Games and Graphics Source Code in C

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Home » C Home » Games and Graphics Home » Number Magic in C.

A D V E R T I S E M E N T

Title	Number Magic in C.
Author	Harsh Birla
Author Email	hbirla [at] gmail.com
Description	It seems to be a illusion, but it involves complete mathematics logic. You are required to think a number between a given range, just think in your mind and don't enter the number. And my program will find out that number by just answering few questions. So just try it......have fun!
Category	C » Games and Graphics
Hits	390449
Code	Select and Copy the Code
#include<stdio.h> #include<conio.h> int generate(void); int fun(int); void main() { int i,a,r; clrscr(); gotoxy(30,12); printf("Harsh Welcomes You! IN THE JARGON OF A NUMBER.."); printf(" Press any key to continue...."); getch(); clrscr(); gotoxy(15,8); printf("Just think a number between 1 to 63 in your mind"); printf(" Think on one "); printf("Do not enter that number"); printf(" I will find that number on your mind...."); printf(" Press any key to continue..."); getch(); clrscr(); gotoxy(20,7); printf("By Just answering few questions...."); printf(" If your number is present in the numbers"); printf(" shown on your screen, Then press P and if not present"); printf(" then press N "); printf(" But please be honest while entering the answer..."); printf(" Press any key to continue..."); getch(); clrscr(); r=generate(); if(r==0) { gotoxy(20,11); printf("You didn't think of any number between 1 to 63"); printf(" So try again..."); } else { gotoxy(30,11); printf("Your number is %d",r); printf(" Surprised! But friends it is not a magic,"); printf(" it just involves some mathematical computation...."); printf(" so guys just try to find out the method. "); printf(" Thank You! "); printf(" Programmed By: Harsh Birla"); } getch(); } int generate() { int a,i,j,f,num[6],n,r=0; char ch[6]; for(j=0;j<=5;j++) { gotoxy(1,7); f=fun(j); for(i=1;i<=63;i++) { //f=fun(j); //printf("%d",f); a=i & f; if(a==f) //gotoxy(5,10); printf(" %d",i); } printf(" Let me remind you if the number is present then"); printf(" press P otherwise press N"); printf(" Enter your answer: "); ch[j]=getche(); printf(" Press any key to continue...."); //clrscr(); if(ch[j]=='p' \|\| ch[j]=='P') { num[j]=1; n=fun(j); r=r+n; } else num[j]=0; getch(); clrscr(); } /* for(j=5;j>=0;j--) { printf("%d",num[j]); // if(ch[j]=='p' \|\| ch[j]=='P') // num[j]=1; // else // num[j]=0; } / // printf(" %d",r); return r; } int fun(int j) { if(j==0) return 1; else return 2fun(j-1); }

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