Circle Through Three Points - Mathematics Source Code in C

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Home » C Home » Mathematics Home » Circle Through Three Points

A D V E R T I S E M E N T

Title	Circle Through Three Points
Author	Sharif Shah Newaj Bhuiyan
Author Email	srabbis [at] hotmail.com
Description	This a program that given the Cartesian coordinates of three points on a plane, will find the equation of the circle through them all. Through this program u can create a equation.
Category	C » Mathematics
Hits	384360
Code	Select and Copy the Code
#include <stdio.h> #include <math.h> #include <conio.h> int main() { clrscr(); double f,g,m,x1,x2,x3,y1,y2,y3; double c,d,h,e,k,r,s; for(;;) { if(scanf("%lf %lf %lf %lf %lf %lf",&x1,&y1,&x2,&y2,&x3,&y3)==EOF) //checking for input break; f = x3x3-x3x2-x1x3+x1x2+y3y3-y3y2-y1y3+y1y2; //formula g = x3y1-x3y2+x1y2-x1y3+x2y3-x2y1; if(g==0) m = 0; else m = (f/g); c = (my2)-x2-x1-(my1); //formula d = (mx1)-y1-y2-(x2m); e = (x1x2)+(y1y2)-(mx1y2)+(mx2y1); h = (c/2); //formula k = (d/2); s = (((h)(h))+((k)(k))-e); r = pow(s,.5); printf("(x"); if(h>=0) printf(" + "); else if(h<0) printf(" - "); if(h<0) h=-h; printf("%.3lf)^2",(h)); printf(" + "); printf("(y"); if(k>=0) printf(" + "); else if(k<0) printf(" - "); if(k<0) k=-k; printf("%.3lf)^2 = %.3lf^2",(k),r); printf(" "); printf("x^2 + y^2"); if(c>=0) printf(" + "); else if(c<0) printf(" - "); if(c<0) c=-c; printf("%.3lfx",c); if(d>=0) printf(" + "); else if(d<0) printf(" - "); if(d<0) d=-d; printf("%.3lfy",d); if(e>=0) printf(" + "); else if(e<0) printf(" - "); if(e<0) e=-e; printf("%.3lf = 0",e); printf(" "); } getch(); return 0; }

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