N-Queen's Problem - Beginners / Lab Assignments Source Code in C

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Home » C Home » Beginners / Lab Assignments Home » N-Queen's Problem

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Title	N-Queen's Problem
Author	Biswajit Debnath
Author Email	biswajitdebnathrbsc [at] yahoo.co.in
Description	This is NQueens' problem. Here n queens will have to be placed in (n x n) matrix in such a way that none will meet any other wile moving horizontally, vertically or along diagonal with respect to its position. The program is able to take any input, but for better output try it with not more than 23.
Category	C » Beginners / Lab Assignments
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/* @@ Problem : This is n-Queen problem. @@ Description : To place n queens in (n x n) matrix such that no queen meets another while moving along the row, col or diag- onal with respect to to its position. @@ Done by : Biswajit Debnath. @@ University : RajaBazar Science College(Calcutta University), Kolkata @@ E-mail : [email protected] @@ Mobile no : 9433 217955 @@ Request : If you have any sugestion or quiry, please do not hesi- tate to mail me. */ #include <iostream.h> #include <ctype.h> #include <stdlib.h> #include <stdio.h> #include <conio.h> void check(int, int, char [100][100]); void print(char [100][100]); int no_of_queens, queen = 2, flagrow = 0, flagcol = 0; int count = 1; char ch, response_row, response_col; int main(void) { int row, col, i; char board[100][100], response; clrscr(); printf(" @@ This is n-queen problem. Enter the number of queens(say n) and watch how computer places them in (n x n) matrix such that none can meet another moving along horizontally, vertically or digonally. "); printf(" Enter the number of queens : "); scanf("%d", &no_of_queens); if(no_of_queens > 23) { printf(" @@ Thought the program is OK for any queen value.But due the configuration of the output screen the output will be tranketed (A very large queen number may cause the system stack overflow). So it is highly recommended that you run the program with maximum queen number 23..."); printf(" Want to continue(Y/N)?"); fflush(stdin); scanf("%c", &response); if(toupper(response) == 'N') return (0); } else if(no_of_queens < 3) { printf("The number of Queen must be greater than 3."); getch(); return (0); } printf("Want a row number below the board(Y/N) : "); fflush(stdin); response_row = (char)getchar(); if(toupper(response_row) == 'Y') flagrow = 1; printf("Want a column number below the board(Y/N) : "); fflush(stdin); response_col = (char)getchar(); if(toupper(response_col) == 'Y') flagcol = 1; clrscr(); printf("M/c in work ! Please Wait..."); // This for-loop is used for checking all the columns of row 0 only... _setcursortype(_NOCURSOR); for(col = 0; col < no_of_queens; col++) { memset(board, '-', sizeof(board)); check( 0, col, board ); } clrscr(); printf("Thank you for seeing this program through."); getch(); return (0); } void check( int r, int c, char board[100][100] ) { int i, j; // Terminating condition for the recursion... if ( ( r == no_of_queens ) && ( c == 0 )) { clrscr(); printf(" (%d-Queen) Set : %d ", no_of_queens, count++); print( board ); fflush(stdin); ch = (char)getch(); clrscr(); if(ch == 'e') exit (0); printf("M/c in work ! Please Wait..."); } // Vertical check... for(i = 0; i < r; i++) { if ( board[i][c] == queen) return; } // Horizontal check... for(j = 0; j < c; j++) { if ( board[r][j] == queen) return; } // Left-Diagonal check... i = r; j = c; do { if ( board[i][j] == queen ) return; i--; j--; } while( i >= 0 && j >= 0 ); // Right-Diagonal check... i = r; j = c; do { if ( board[i][j] == queen ) return; i--; j++; } while( i >= 0 && j < no_of_queens ); // Placing the queen if the ckecked position is OK... board[r][c] = queen; r++; // This for-loop is used for checking all the columns for each row //starting from 1 upto the end... for(int p = 0; p < no_of_queens; p++) check(r, p, board); for(int h = 0; h < no_of_queens; h++) board[r - 1][h] = '-'; } void print(char board[100][100]) { for(int i = 0; i < no_of_queens; i++) { if(flagrow == 1) printf("%3d", i + 1); for(int j = 0; j < no_of_queens; j++) { if(board[i][j] == queen) { textcolor(RED); cprintf("%3c", queen); } else { textcolor(8); //dark gray cprintf("%3c", 22); } } printf(" "); } textcolor(7); if(flagcol == 1) { if(flagrow) printf(" "); for(i = 0; i < no_of_queens; i++) printf("%3d", i + 1); } gotoxy(62, 1); printf("Press E to exit."); textcolor(7); }

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