Calender (for all years) - Mathematics Source Code in C

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Home » C Home » Mathematics Home » Calender (for all years)

A D V E R T I S E M E N T

Title	Calender (for all years)
Author	K.E.Joseph
Author Email	kejoseph77 [at] yahoo.co.in
Description	Calender (for all years)
Category	C » Mathematics
Hits	377426
Code	Select and Copy the Code
/* ?????????????????????????????????????????????????????????????????????????? ???? ? CALENDAR ?????????????????????????????????????????????????????????????????????????? ????/ # include <stdio.h> # include <conio.h> # include <string.h> # include <process.h> static char month[] = { "", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec", }; static char weekday[]={ "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat", }; main() { int mm, yy; int key; clrscr(); printf( " ???????????????????????????????????????????????????"); printf( " ? ?"); printf( " ? Calender ?"); printf( " ? ?"); printf( " ??????????????????????????????????????????????????? "); printf(" *Press any key*"); getch(); clrscr(); printf(" ???????????????????????????????????????????????????"); printf(" ?Calender from 01-01-01 to infinity.... ?"); printf(" ?Enter In this format: MM YYYY ?"); printf(" ?Writen in C language.. ?"); printf(" ?Design by: K.E. Joseph ?"); printf(" ??????????????????????????????????????????????????? "); l1: printf(" Please Enter month & year :"); scanf("%d %d", &mm, &yy); if(mm < 1 \|\| yy<1) { printf(" Enter Correct data.. "); goto l1; } while(1) { clrscr(); display_calendar(mm, yy); puts("For navigation, use the arrow keys."); puts("To enter another date, press the Insert key."); puts("For RESET press INSERT key"); puts("Press ESC to exit."); printf(" ???????????????????????????????????????????????????"); printf(" ? Design by :K.Ebenezer Joseph ?"); printf(" ??????????????????????????????????????????????????? "); key = getkey(); switch(key) { case 72://up arrow key yy++; break; case 80://down arrow key yy--; break; case 75://left arrow key if(mm==1) { yy--; mm=12; } else mm--; break; case 77://right arrow key mm++; if(mm>12) { yy++; mm%=12; } if(mm==0) mm=12; break; case 1://escape key exit(0); case 82://Insert key return main(); } } } display_calendar(int mm, int yy) { char i, days; char first_day; char lines=1; first_day=find_day(1, mm, yy); printf(" ???????????????????????????????????????????????????"); printf(" ? %s-%d ?", month[mm],yy); printf(" ??????????????????????????????????????????????????? "); for(i=0; i<7;i++) printf("%s ", weekday[i]); puts(""); for(i=0; i<first_day;i++) printf(" "); //Find total no. of days in the month if (mm!=2) switch(mm) { case 4: case 6: case 9: case 11: days=30; break; default: days=31; } else isleapyear(yy)?(days=29):(days=28); for(i=1;i<=days;i++) { printf("%d ", i); if((i+first_day)%7==0) { puts(""); lines++; } } puts(" "); switch(lines) { case 4: puts(""); case 5: puts(""); } } find_day(int dd, int mm, int yy) { int odddays, leapyear; leapyear=isleapyear(yy); odddays=odddayyear(yy)+odddaymonth(mm,leapyear)+odddayday(dd); odddays %= 7; return odddays; } /Every 4th year is a leap year, however centuries are not leap years except those divisible by 400 for example: 1990 is NOT a leap year 2000 is a leap year 2004 is a leap year / isleapyear(int yy) { if(yy%4==0 && (yy%100!=0 \|\| yy%400==0)) return 1; else return 0; } //Calculates odd days upto first day of year odddayyear(int yy) { int odddays=0; yy-=1; if(yy>=400) yy%=400; if(yy>=100) { odddays=yy/100; odddays = 5; yy%=100; } odddays += yy; odddays += yy/4; return odddays; } odddaymonth(int mm, char leapyear) { switch(mm) { case 1: return 0; case 2: return 3; case 3: case 11: return leapyear?4:3; case 4: case 7: return leapyear?0:6; case 5: return leapyear?2:1; case 6: return leapyear?5:4; case 8: return leapyear?3:2; case 9: case 12: return leapyear?6:5; case 10: return leapyear?1:0; } } odddayday(int dd) { return dd%7; } //Returns scan code of the key that has been hit #include "dos.h" getkey() { union REGS i, o; while (!kbhit()) ; i.h.ah=0; int86(22, &i, &o); return (o.h.ah); } /*****************H I N T S ******************* Every 4th year is a leap year, however centuries are not leap years except those divisible by 400 for example: 1990 is NOT a leap year 2000 is a leap year 2004 is a leap year for example: ------------- 1 ordinary year = 365 days = (52 weeks + 1 day) = 1 odd day that's why if this year 23th August is on Tuesday, it will be on Wednesday next year 1 leap year = 366 days = (52 weeks + 2 days) = 2 odd days 100 years = 76 ordinary years + 24 leap years = [(7652) weeks+76 days] + [(2452) weeks+48 days] = 5200 weeks + 124 days = 5217 weeks + 5 days = 5 odd days 200 years = 10 odd days = 3 odd days 300 years = 15 odd days = 1 odd days 400 years = 20 + 1 odd days = 0 days 800 years = 0 odd days Sunday is the 0th odd day, Monday the 1st odd day and so on*/

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