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Title To Convert an no. entered by the user (digits can be
Author vipin
Author Email vipin18gupta
Description This Program takes the no. entered by the user as an string String is converted into a series of int type arrays.The main Objective is to tackle digits greater than 12.Special attention has been given to commas & fullstop used to separate words
Category C » C on Unix
Hits 7422
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Code: #include<iostream.h> #include<conio.h> #include<string.h> #include<stdio.h> int fchar=0; char ones[22][22]={"zero","one","two","three","four","five","six","seven","eigh t","nine","ten", "eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","e ighteen","nineteen"}; char first[22][22]={"Zero","One","Two","Three","Four","Five","Six","Seven","Eig ht","Nine","Ten", "Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","E ighteen","Nineteen"}; char tens[10][10]={"twenty","thirty","fourty","fifty","sixty","seventy","eighty ","ninety"}; char sec[10][10]={"Twenty","Thirty","Fourty","Fifty","Sixty","Seventy","Eighty" ,"Ninety"}; char tenz[10][10]={"hundred","thousand","million","billion"}; void fun2(long); void main() { clrscr(); char string[50]; textbackground(BLUE); textcolor(GREEN); long i,j; long m=1; long n[10]={0,0,0,0,0,0,0,0,0,0},no; cout<<"Enter the no. "; cin>>string; for(i=0;string[i]!='

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